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x^2-1580x+599500=0
a = 1; b = -1580; c = +599500;
Δ = b2-4ac
Δ = -15802-4·1·599500
Δ = 98400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{98400}=\sqrt{400*246}=\sqrt{400}*\sqrt{246}=20\sqrt{246}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1580)-20\sqrt{246}}{2*1}=\frac{1580-20\sqrt{246}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1580)+20\sqrt{246}}{2*1}=\frac{1580+20\sqrt{246}}{2} $
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